Question 17
Mole Concept and StoichiometryWhat mass of K2CrO4 is required to prepare 250cm3 of 0.020 mol dm-3 solution? [K2CrO4 = 194.2g mol-1]
- A.0.97 g
- B.9.70 g
- C.19.42 g
- D.97.10 g
Show the answer and explanation
Answer: A (0.97 g)
Explanation
Moles = 0.020 × 0.250 = 0.005 mol. Mass = 0.005 × 194.2 = 0.971 g.