Question 16
Solubility and SolutionsThe solubility of a salt of molar mass 101g at 20°C is 0.34 mol dm−3. If 3.40g of the salt is dissolved completely in 250cm3 of water in a beaker, the resulting solution is
- A.a suspension
- B.saturated
- C.unsaturated
- D.supersaturated
Show the answer and explanation
Answer: C (unsaturated)
Explanation
A saturated solution would hold 0.34 × 101 × 0.25 ≈ 8.6 g in 250 cm3. Only 3.40 g is dissolved, so the solution is unsaturated.