Question 5
Gas LawsWhat is the temperature of a given mass of a gas initially at 0°C and 9 atm, if the pressure is reduced to 3 atm at constant volume?
- A.91 K
- B.182 K
- C.273 K
- D.819 K
Show the answer and explanation
Answer: A (91 K)
Explanation
At constant volume P/T is constant: 9/273 = 3/T2, so T2 = 273 × 3/9 = 91 K.