Question 27
Energy Changes32g of anhydrous copper (II) tetraoxosulphate (VI) dissolved in 1dm3 of water generated 13.0kJ of heat. The heat of solution is [Cu = 64, S = 32, O = 16]
- A.26.0 kJmol−1
- B.65.0 k Jmol−1
- C.130.0 kJmol−1
- D.260.0kJmol−1
Show the answer and explanation
Answer: B (65.0 k Jmol−1)
Explanation
Molar mass of CuSO4 = 160, so 32 g = 0.2 mol. Heat per mole = 13.0/0.2 = 65.0 kJ mol−1 (given out, so ΔH = −65 kJ mol−1).