Question 2
Chemical Formulae and Equations2.85 g of an oxide of copper gave 2.52 g of copper on reduction and 1.90 g of another oxide gave 1.52 g of copper on reduction. The data above illustrates the law of
- A.constant composition
- B.conservation of mass
- C.reciprocal proportions
- D.multiple proportions
Show the answer and explanation
Answer: D (multiple proportions)
Explanation
Two different oxides of the same two elements are compared. Per gram of oxygen the copper masses are 2.52/0.33 ≈ 7.6 g and 1.52/0.38 = 4.0 g, a simple ratio of about 2 : 1, which is the law of multiple proportions.