Question 24
ElectrolysisHow many moles of copper would be deposited by passing 3F of electricity through a solution of copper (II) tetraoxosulphate (VI)? [F = 96 500 C mol-1]
- A.0.5
- B.1.0
- C.1.5
- D.3.0
Show the answer and explanation
Answer: C (1.5)
Explanation
Cu2+ + 2e− → Cu, so 2 F deposit 1 mol of copper. 3 F deposit 3/2 = 1.5 mol.