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JAMB Chemistry 1995 Question 21

Question 21

Acids, Bases and Salts

What is the pH of a 2.50 x 10-5 M solution of sodium hydroxide?

  1. A.3.6
  2. B.5.0
  3. C.9.4
  4. D.12.0
Show the answer and explanation

Answer: C (9.4)

Explanation

[OH−] = 2.50 × 10-5, so pOH = −log(2.50 × 10-5) = 4.6. pH = 14 − 4.6 = 9.4.