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JAMB Chemistry 1994 Question 4

Question 4

Mole Concept and Stoichiometry

8 g CH4 occupies 11.2 dm3 at s.t.p. What volume would 22 g of CH3CH2CH3 occupy under the same condition? [C = 12, H = 1]

  1. A.3.7 dm3
  2. B.11.2 dm3
  3. C.22.4 dm3
  4. D.33.6 dm3
Show the answer and explanation

Answer: B (11.2 dm3)

Explanation

Propane, C3H8, has M = 44, so 22 g is 0.5 mol, the same number of moles as 8 g of CH4. It therefore occupies the same 11.2 dm3.