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JAMB Chemistry 1992 Question 25

Question 25

Redox Reactions

2S2O32− + I2 → S4O62− + 2I−. In the reaction above, the oxidising agent is

  1. A.S2O32−
  2. B.I2
  3. C.S4O62−
  4. D.I−.
Show the answer and explanation

Answer: B (I2)

Explanation

Iodine goes from 0 in I2 to −1 in I−, so it is reduced. The substance reduced is the oxidising agent.