passwella.
Menu

JAMB Chemistry 1992 Question 11

Question 11

Radioactivity

147N + X → 178O + 11H. In the above reaction, X is a

  1. A.neutron
  2. B.helium atom
  3. C.lithium atom
  4. D.deuterium atom.
Show the answer and explanation

Answer: B (helium atom)

Explanation

Mass numbers: 14 + a = 17 + 1, so a = 4. Atomic numbers: 7 + z = 8 + 1, so z = 2. X is 42He, a helium nucleus.