Question 22
Mole Concept and StoichiometryWhat volume of CO2 at s.t.p would be obtained by reacting 10 cm3 of 0.1 M solution of anhydrous sodium trioxocarbonate (IV) with excess acid? [G.M.V at s.t.p = 22.4 dm3]
- A.2.240 cm3
- B.22.40 cm3
- C.224.0 cm3
- D.2240 cm3.
Show the answer and explanation
Answer: B (22.40 cm3)
Explanation
Moles of Na2CO3 = 0.1 × 10/1000 = 0.001, giving 0.001 mol of CO2. Volume = 0.001 × 22 400 cm3 = 22.4 cm3.