passwella.
Menu

JAMB Chemistry 1990 Question 23

Question 23

Electrolysis

0.1 faraday of electricity deposited 2.95 g of nickel during electrolysis of an aqueous solution. Calculate the number of moles of nickel that will be deposited by 0.4 faraday. [Ni = 58.7]

  1. A.0.20
  2. B.0.30
  3. C.0.04
  4. D.5.87
Show the answer and explanation

Answer: A (0.20)

Explanation

0.1 F deposits 2.95 ÷ 58.7 = 0.0503 mol of nickel. Four times the charge (0.4 F) deposits 4 × 0.0503 ≈ 0.20 mol.