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JAMB Chemistry 1988 Question 3

Question 3

Chemical Formulae and Equations

2.25 g of a sample of an oxide of copper on reduction gave 2.0 g of copper. 2.50 g of another oxide of copper on reduction also gave 2.0 g of copper. These results are in accordance with the law of

  1. A.constant composition
  2. B.conservation of matter
  3. C.multiple proportions
  4. D.definite proportions.
Show the answer and explanation

Answer: C (multiple proportions)

Explanation

The same 2.0 g of copper combines with 0.25 g and 0.50 g of oxygen in the two oxides. These masses are in the simple ratio 1 : 2, which is the law of multiple proportions.