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JAMB Chemistry 1988 Question 20

Question 20

Volumetric Analysis

What volume of a 0.1 M H3PO4 will be required to neutralize 45.0 cm3 of a 0.2 M NaOH?

  1. A.10.0 cm3
  2. B.20.0 cm3
  3. C.27.0 cm3
  4. D.30.0 cm3
Show the answer and explanation

Answer: D (30.0 cm3)

Explanation

H3PO4 + 3NaOH → Na3PO4 + 3H2O. NaOH = 0.2 × 45/1000 = 0.009 mol, so acid = 0.003 mol. Volume = 0.003/0.1 = 0.030 dm3 = 30.0 cm3.