Question 15
Mole Concept and Stoichiometry1.34 g of hydrated sodium tetraoxosulphate (VI) was heated to give an anhydrous salt weighing 0.71 g. The formula of the hydrated salt is [Na = 23, S = 32, O = 16, H = 1]
- A.Na2SO4.7H2O
- B.Na2SO4.3H2O
- C.Na2SO4.2H2O
- D.Na2SO4.H2O
Show the answer and explanation
Answer: A (Na2SO4.7H2O)
Explanation
Anhydrous Na2SO4: 0.71/142 = 0.005 mol. Water lost: 0.63 g = 0.035 mol. Ratio 0.035/0.005 = 7, so Na2SO4.7H2O.