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JAMB Chemistry 1983 Question 49

Question 49

Mole Concept and Stoichiometry

Zn + H2SO4 → ZnSO4 + H2.
In the above reaction how much zinc will be left undissolved if 2.00 g of zinc is treated with 10 cm3 of 1.0 M of H2SO4? [Zn = 65, S = 32, O = 16, H = 1]

  1. A.1.35 g
  2. B.1.00 g
  3. C.0.70 g
  4. D.0.65 g
  5. E.0.00 g
Show the answer and explanation

Answer: A (1.35 g)

Explanation

Acid = 0.010 × 1.0 = 0.01 mol, which dissolves 0.01 mol Zn = 0.65 g. Zinc left = 2.00 − 0.65 = 1.35 g.