Question 17
ElectrolysisIn the above experiment (Fig. 2), a current was passed for 10 minutes and 0.63 g of copper was found to be deposited on the cathode of CuSO4 cells. The weight of silver deposited on the cathode of AgNO3 cell during the same period would be [Cu = 63, Ag = 108]

- A.0.54 g
- B.1.08 g
- C.1.62g
- D.2.16 g
- E.3.24 g.
Show the answer and explanation
Answer: D (2.16 g)
Explanation
0.63 g Cu = 0.01 mol, which needed 0.02 mol of electrons (Cu2+). The same charge deposits 0.02 mol Ag (Ag+) = 0.02 × 108 = 2.16 g.