Question 8
ElectrolysisA current of 10.0A was passed for 1 hour through a solution of copper (II) sulphate between the copper electrodes. Which of the following observations would be correct? (1 Faraday = 96,500 coulombs)
(i) 0.186 mole of copper is dissolved from the anode
(ii) 0.372 mole of copper is deposited on the cathode
(iii) the original Cu2+ ion concentration of the solution remains unchanged.
(iv) the original Cu2+ ion concentration of the solution decreases
- A.(i) and (ii)
- B.(i) and (iii)
- C.(i) and (iv)
- D.(ii) and (iii)
- E.(ii) and (iv)
Show the answer and explanation
Answer: B ((i) and (iii))
Explanation
Charge = 10 × 3600 = 36,000 C = 0.373 F, which moves 0.186 mol Cu (2 F per mole). With copper electrodes the anode dissolves as fast as the cathode gains copper, so [Cu2+] stays the same.