Question 22
Mole Concept and Stoichiometry1.00 g of a mixture of calcium carbonate and calcium oxide liberated 0.33 g of carbondioxide on strong heating. The percentage of calcium oxide in the mixture is (Ca = 40, C = 12, O = 16)
- A.5
- B.15
- C.25
- D.35
- E.50
Show the answer and explanation
Answer: C (25)
Explanation
100 g CaCO3 gives 44 g CO2, so 0.33 g CO2 came from 0.75 g CaCO3. The rest, 0.25 g, is CaO: 25%.