Question 14
Mole Concept and StoichiometryWhat weight of sodium hydroxide is required to make 500 cm3 of 0.2 M solution? (Na = 23, O = 16, H = 1)
- A.40 g
- B.20 g
- C.10 g
- D.4 g
- E.2 g
Show the answer and explanation
Answer: D (4 g)
Explanation
Moles = 0.5 × 0.2 = 0.1 mol; mass = 0.1 × 40 = 4 g.