Question 38
Mole Concept and StoichiometryPure sulphuric acid is a liquid of 1.84 density. What volume of it would be required to prepare 250 cm3 of 0.2 M solution? (H = 1, S = 32, O = 16)
- A.2.00
- B.2.66
- C.3.00
- D.3.66
- E.4.00
Show the answer and explanation
Answer: B (2.66)
Explanation
Moles needed = 0.250 × 0.2 = 0.05 mol, which is 0.05 × 98 = 4.9 g. Volume = mass/density = 4.9/1.84 = 2.66 cm3.