Question 13
Latitude, Longitude and TimeThe distance of Leningrad (lat 60°N long 30°E) from the equator is approximately
- A.8880km
- B.6660km
- C.5700km
- D.3330km
- E.1110km
Show the answer and explanation
Answer: B (6660km)
Explanation
1° of latitude ≈ 111 km, so 60 × 111 = 6,660 km.