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WAEC Further Mathematics 2025 Question 28

Question 28

Dynamics

A particle of mass 4 kg moves from point P with velocity (3i + 10j) ms−1 and reached point Q with velocity (2i + 3j) ms−1. Find the change in momentum of the particle from P to Q.

  1. A.−4i + 28j
  2. B.−4i − 28j
  3. C.4i − 28j
  4. D.4i + 28j
Show the answer and explanation

Answer: B (−4i − 28j)

Explanation

Change in momentum = m(v − u) = 4[(2i + 3j) − (3i + 10j)] = 4(−i − 7j) = −4i − 28j.