Question 34
IntegrationEvaluate: ∫(2x + 1)3 dx.
- A.8(2x + 1)2 + k
- B.6(2x + 1)2 + k
- C.⅙(2x + 1)4 + k
- D.⅛(2x + 1)4 + k
Show the answer and explanation
Answer: D (⅛(2x + 1)4 + k)
Explanation
∫(2x + 1)³ dx = (2x + 1)⁴/(4 × 2) + k = ⅛(2x + 1)⁴ + k.
Evaluate: ∫(2x + 1)3 dx.
Answer: D (⅛(2x + 1)4 + k)
∫(2x + 1)³ dx = (2x + 1)⁴/(4 × 2) + k = ⅛(2x + 1)⁴ + k.