Question 19
DynamicsA particle began to move at 27 ms−1 along a straight line with constant retardation of 9 ms−2. Calculate the time it took the particle to come to a stop.
- A.4 sec.
- B.3 sec.
- C.2 sec.
- D.1 sec.
Show the answer and explanation
Answer: B (3 sec.)
Explanation
v = u − at: 0 = 27 − 9t, so t = 3 s.