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WAEC Further Mathematics 2018 Question 10

Question 10

Polynomials

Resolve (3x − 1)/(x − 2)2, x ≠ 2 into partial fractions

  1. A.3/(x − 2)2 + 5/(x − 2)
  2. B.3/(x − 2) + 5/(x − 2)2
  3. C.3/(x − 2)2 − 7/(x − 2)
  4. D.3/(x − 2) − 7/(x − 2)2
Show the answer and explanation

Answer: B (3/(x − 2) + 5/(x − 2)2)

Explanation

3x − 1 = A(x − 2) + B: A = 3, and x = 2 gives B = 5. So 3/(x − 2) + 5/(x − 2)².