passwella.
Menu

WAEC Further Mathematics 2011 Question 8

Question 8

Polynomials

Solve 3x2 + 4x + 1 > 0.

  1. A.x < −1, x < −⅓
  2. B.x > −1
  3. C.x > −⅓, x < −1
  4. D.x < −⅓, x < −⅓
Show the answer and explanation

Answer: C (x > −⅓, x < −1)

Explanation

3x2 + 4x + 1 = (3x + 1)(x + 1). The product is positive when both factors have the same sign: x > −⅓ or x < −1.