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WAEC Further Mathematics 2011 Question 36

Question 36

Dynamics

A particle starts from rest and moves in a straight line such that its velocity, V, at time t seconds is given by v = (3t2 − 2t)ms−1. Determine the acceleration when t = 2 seconds.

  1. A.4 ms−2
  2. B.6 ms−2
  3. C.8 ms−2
  4. D.10 ms−2
Show the answer and explanation

Answer: D (10 ms−2)

Explanation

a = dv/dt = 6t − 2. At t = 2: a = 12 − 2 = 10 ms−2.