WAEC Further Mathematics 2011 Question 13

Question 13

Differentiation

Find limx→3 (x + 3)/(x2 − x − 12)

  1. A.−1
  2. B.−1/7
  3. C.1/7
  4. D.1
Show the answer and explanation

Answer: A (−1)

Explanation

The denominator is not zero at x = 3, so substitute: (3 + 3)/(9 − 3 − 12) = 6/(−6) = −1.