Question 20
DifferentiationIf f(x) = mx2 − 6x − 3 and f′(1) = 12, find the value of constant m.
- A.9
- B.3
- C.−3
- D.−4
Show the answer and explanation
Answer: A (9)
Explanation
f′(x) = 2mx − 6, so f′(1) = 2m − 6 = 12 and m = 9.
If f(x) = mx2 − 6x − 3 and f′(1) = 12, find the value of constant m.
Answer: A (9)
f′(x) = 2mx − 6, so f′(1) = 2m − 6 = 12 and m = 9.