WAEC Further Mathematics 2006 Question 14

Question 14

Indices and Logarithms

Evaluate log0.25 8.

  1. A.3/2
  2. B.2/4
  3. C.2/3
  4. D.−3/2
Show the answer and explanation

Answer: D (−3/2)

Explanation

Let log0.25 8 = x, so (¼)x = 8, i.e. 2−2x = 2³. Then −2x = 3 and x = −3/2.