Question 9
ElectrostaticsCalculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm
- A.18.57NC−1
- B.53.06NC−1
- C.2.28NC−1
- D.0.80NC−1
Show the answer and explanation
Answer: A (18.57NC−1)
Explanation
E = V/d = 6.5 ÷ 0.35 = 18.57 N/C (or V/m).