Question 27
Linear and Simultaneous EquationsThe sum of the ages of a man and his son is 67 years. Six years ago the man's age exceeded 5 times the age of his son by 1. Find their present ages.
- A.Man = 52 years son = 15 years
- B.Man = 52 years son = 16 years
- C.Man = 55 years son = 10 years
- D.Man = 60 years son = 10 years
Show the answer and explanation
Answer: A (Man = 52 years son = 15 years)
Explanation
x + y = 67 and x − 6 = 5(y − 6) + 1 give x − 5y = −23; subtracting, 6y = 90, so y = 15 and x = 52.