Question 10
IntegrationIntegrate with respect to t, (2t3 + 2t)/t
- A.2t3/3 − 2t + k
- B.2t3/3 + 2t + k
- C.t3 − 2t + k
- D.t3 + 2t + k
Show the answer and explanation
Answer: B (2t3/3 + 2t + k)
Explanation
Simplify first: (2t³ + 2t)/t = 2t² + 2. Then ∫(2t² + 2)dt = 2t³/3 + 2t + k.