UI Post-UTME Mathematics 2012 past questions and answers

19 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 2

Mensuration of Solids

An open wooden box is made up of material which is 4cm thick. The inner dimensions are 16cm by 12cm by 9cm. Calculate the volume of wood used in making the box

  1. A.3500cm3
  2. B.6240cm3
  3. C.1728cm3
  4. D.4512cm3
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Answer: D (4512cm3)

Explanation

With 4 cm walls on all sides and the base (open top), the outside is 24 × 20 × 13 = 6240 cm³; inside is 16 × 12 × 9 = 1728 cm³; wood = 4512 cm³.

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Question 3

Mensuration of Solids

A cuboid has a length 13cm, width 9cm and height 8cm. calculate its surface area

  1. A.600cm2
  2. B.586cm2
  3. C.700cm2
  4. D.450cm2
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Answer: B (586cm2)

Explanation

2(13 × 9 + 13 × 8 + 9 × 8) = 2(117 + 104 + 72) = 586 cm².

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Question 4

Mensuration of Plane Shapes

In the figure above, BK = KC = 5cm. AK = 3cm. find the area of the triangle.

Diagram for this question
  1. A.30cm2
  2. B.38cm2
  3. C.15cm2
  4. D.25cm2
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Answer: C (15cm2)

Explanation

AK is the height and the base BC = 10 cm, so area = ½ × 10 × 3 = 15 cm².

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Question 5

Triangles and Quadrilaterals

Find the third angle of a triangle when x = 60° and if the other two angles are (x + 30°) and (2x − 65°).

  1. A.35°
  2. B.45°
  3. C.55°
  4. D.15°
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Answer: A (35°)

Explanation

The two angles are 90° and 55°, so the third is 180° − 145° = 35°.

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Question 6

Logarithms

Simplify log16/log32

  1. A.3
  2. B.4/5
  3. C.2
  4. D.½
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Answer: B (4/5)

Explanation

log 2⁴/log 2⁵ = 4/5.

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Question 7

Latitude and Longitude

Find the distance between A(lat. 56°S, long 80°E) and B(lat. 65°N, long 80°E). Take π = 3.142 and R = 6400km

  1. A.13518km
  2. B.65200km
  3. C.11425km
  4. D.13242km
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Answer: A (13518km)

Explanation

They are on the same meridian, 56° + 65° = 121° apart: 121/360 × 2 × 3.142 × 6400 ≈ 13,518 km.

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Question 8

Latitude and Longitude

Find the radius of the parallel latitude of latitude 50°N, given that R = 6400km

  1. A.3273km
  2. B.4114km
  3. C.4270km
  4. D.1212km
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Answer: B (4114km)

Explanation

r = R cos 50° = 6400 × 0.6428 ≈ 4114 km.

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Question 9

Mensuration of Solids

A hemispherical bowl has a radius of 9cm. Calculate its total surface area and its volume

  1. A.700cm2, 1527cm3
  2. B.8800cm2, 3600cm3
  3. C.763.5cm2, 1527cm3
  4. D.1821cm2, 3822cm3
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Answer: C (763.5cm2, 1527cm3)

Explanation

Total surface area of a solid hemisphere = 3πr² = 3 × 3.142 × 81 ≈ 763.5 cm²; volume = ⅔πr³ = ⅔ × 3.142 × 729 ≈ 1527 cm³.

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Question 10

Mensuration of Plane Shapes

Calculate the circumference and area of a circle of radius 10.5cm

  1. A.43cm, 80cm2
  2. B.36cm, 42cm2
  3. C.49cm, 109cm2
  4. D.66cm, 346cm2
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Answer: D (66cm, 346cm2)

Explanation

C = 2πr = 2 × 22/7 × 10.5 = 66 cm; A = πr² ≈ 346.5 cm².

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Question 11

Surds

Find the positive square root of 7 − 2√10

  1. A.√5 − √2
  2. B.√5 + √2
  3. C.√2 − √5
  4. D.3
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Answer: A (√5 − √2)

Explanation

(√5 − √2)² = 7 − 2√10, and √5 − √2 is positive.

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Question 12

Number Bases

Evaluate (1112)2 − (1012)2 leaving your answer in base two.

  1. A.10
  2. B.00
  3. C.1100
  4. D.11000
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Answer: D (11000)

Explanation

7² − 5² = 24 = 11000₂.

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Question 13

Logarithms

Given that log102 = 0.3, solve the equation 2x = 5

  1. A.11/5
  2. B.2/5
  3. C.7/3
  4. D.5/3
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Answer: C (7/3)

Explanation

x = log 5/log 2 = 0.7/0.3 = 7/3.

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Question 14

Indices

Simplify 8n × 22n ÷ 43n

  1. A.2−n
  2. B.8n
  3. C.21
  4. D.6
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Answer: A (2−n)

Explanation

2³ⁿ × 2²ⁿ ÷ 2⁶ⁿ = 2⁻ⁿ.

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Question 15

Indices

Solve the simultaneous equation y = 3x; 3x−y = 1/81

  1. A.(1, 3)
  2. B.(2, 6)
  3. C.(3, 9)
  4. D.(4, 12)
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Answer: B ((2, 6))

Explanation

x − y = −4 and y = 3x give x = 2, y = 6.

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Question 16

Logarithms

Find the value of x such that log5(x + 2) + log5(x − 2) = 1

  1. A.3
  2. B.4
  3. C.5
  4. D.6
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Answer: A (3)

Explanation

x² − 4 = 5, so x = 3.

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Question 18

Commercial Arithmetic

A lady invested a sum of money at 4% per annum simple interest. Find the sum invested if after 3years it amounts to N7,000.00

  1. A.N6,250.00
  2. B.N6,160.00
  3. C.N5,833.33
  4. D.N5,500.00
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Answer: A (N6,250.00)

Explanation

Amount = P(1 + 0.12) = 7000, so P = N6,250.

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Question 19

Number Bases

Convert the binary number 1111.101 to base ten.

  1. A.11.101
  2. B.11.65
  3. C.15.625
  4. D.11.125
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Answer: C (15.625)

Explanation

8 + 4 + 2 + 1 + 0.5 + 0.125 = 15.625.

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Question 20

Fractions, Decimals and Approximation

Approximate 0.00629946 to 3 significant figures.

  1. A.630
  2. B.0.006
  3. C.0.00
  4. D.0.00630
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Answer: D (0.00630)

Explanation

The first three significant figures are 6, 2, 9; rounding gives 0.00630.

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Question 44

Matrices and Determinants

Solve for x and y: (1 1; 3 y)(x; 1) = (4; 1) (matrix rows separated by semicolons)

  1. A.x = 3, y = 8
  2. B.x = 8, y = 3
  3. C.x = 3, y = −8
  4. D.x = 8, y = −3
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Answer: C (x = 3, y = −8)

Explanation

x + 1 = 4 gives x = 3; 3x + y = 1 gives y = 1 − 9 = −8.

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