Question 15
Coordinate GeometryFind the equation of the circle which has its centre at (−2, 3) and passes through the point (4, 5).
- A.x2 + 2x + y2 − 3y − 27 = 0
- B.x2 + y2 + 4x − 6y − 27 = 0
- C.x2 + y2 − 4x + 6y + 27 = 0
- D.x2 + y2 − 2x + 3y − 27 = 0
Show the answer and explanation
Answer: B (x2 + y2 + 4x − 6y − 27 = 0)
Explanation
r² = 6² + 2² = 40. (x + 2)² + (y − 3)² = 40 expands to x² + y² + 4x − 6y − 27 = 0.