Question 13
TrigonometrySolve sin2x + 2 sin x + 1 = 0 for 0° < x < 360°.
- A.90°
- B.180°
- C.210°
- D.270°
Show the answer and explanation
Answer: D (270°)
Explanation
(sin x + 1)² = 0, so sin x = −1, which happens at x = 270°.
Solve sin2x + 2 sin x + 1 = 0 for 0° < x < 360°.
Answer: D (270°)
(sin x + 1)² = 0, so sin x = −1, which happens at x = 270°.