Question 12
BearingsIf the bearing of a town B from A is 145°, the bearing of A from B is
- A.305°
- B.325°
- C.35°
- D.145°
Show the answer and explanation
Answer: B (325°)
Explanation
A back bearing differs by 180°: 145° + 180° = 325°.
If the bearing of a town B from A is 145°, the bearing of A from B is
Answer: B (325°)
A back bearing differs by 180°: 145° + 180° = 325°.