Question 17
IntegrationFind the value of ∫0π/2(2π + 2cos 2x)dx
- A.π2 + 1
- B.π2
- C.π2 − 4
- D.π2 + 3
Show the answer and explanation
Answer: B (π2)
Explanation
The integral is 2πx + sin 2x. At π/2: π² + sin π = π². At 0: 0. Answer π².
Find the value of ∫0π/2(2π + 2cos 2x)dx
Answer: B (π2)
The integral is 2πx + sin 2x. At π/2: π² + sin π = π². At 0: 0. Answer π².