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JAMB Mathematics 2023 past questions and answers

4 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 6

Linear and Simultaneous Equations

Solve the equations: P2 + q2 = 29, P + q = 7

  1. A.(5,3) and (3,5)
  2. B.(5,2) and (5,3)
  3. C.(2,5) and (5,2)
  4. D.(2,3) and (3,5)
Show the answer and explanation

Answer: C ((2,5) and (5,2))

Explanation

Substitute p = 7 − q: (7 − q)² + q² = 29 gives q² − 7q + 10 = 0, so q = 2 or 5. The solutions are (5, 2) and (2, 5).

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Question 17

Algebraic Expressions

Make m the subject of the formula P = 1 − a/5 (b + 3/7 m)

  1. A.m = −(7b/3 + 5/a(p − 1))
  2. B.m = 7/3[b − 5/a(p − 1)]
  3. C.m = −7/3[b + 5/a(p − 1)]
  4. D.m = −7/3[b + (5p − 1)/a]
Show the answer and explanation

Answer: C (m = −7/3[b + 5/a(p − 1)])

Explanation

(a/5)(b + 3m/7) = 1 − P, so b + 3m/7 = 5(1 − P)/a. Then 3m/7 = −[b + 5(P − 1)/a], so m = −7/3[b + 5/a(P − 1)].

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Question 20

Number Bases

In base ten, the number 101101 (base2) equals

  1. A.15
  2. B.45
  3. C.32
  4. D.90
Show the answer and explanation

Answer: B (45)

Explanation

101101₂ = 32 + 8 + 4 + 1 = 45.

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Question 36

Algebraic Expressions

Make t the subject of the formula n = zt + ½at2

  1. A.1/a[z ± √(z2 − 2an)]
  2. B.1/a[z ± √(z2 + 2an)]
  3. C.1/a[−z ± √(z2 + 2an)]
  4. D.1/a[−z ± √(z2 − 2an)]
Show the answer and explanation

Answer: C (1/a[−z ± √(z2 + 2an)])

Explanation

Rearrange as at² + 2zt − 2n = 0. The quadratic formula gives t = [−2z ± √(4z² + 8an)]/(2a) = (1/a)[−z ± √(z² + 2an)].

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