Question 7
Quadratic EquationsThe solution of the quadratic equation bx2 + cx + a = 0, is given by
- A.x = (−c ± √(c2 − 4ab))/2b
- B.x = (−b ± √(b2 − 4ac))/2a
- C.x = (c ± √(b2 − 4ac))/2b
- D.x = (b ± √(b2 + 4ac))/2a
- E.x = c ± √(c2 − 4ab)/2b
Show the answer and explanation
Answer: A (x = (−c ± √(c2 − 4ab))/2b)
Explanation
In the usual formula the coefficient of x² is now b, of x is c, and the constant is a. So x = (−c ± √(c² − 4ab))/2b.