Question 4
TrigonometryIn the above diagram, angle QPR = 90°, angle PSR = 90° and PR = 5 units. Find the length of QS.

- A.5 tan 25° sin 65°
- B.5 cot 25° sin 65°
- C.5 tan 25° cos 65°
- D.5 cot 25° cos 65°
- E.5 cosec 25°.
Show the answer and explanation
Answer: B (5 cot 25° sin 65°)
Explanation
In triangle PQR, <R = 65°, so PS = PR sin 65° = 5 sin 65°. In triangle PQS, tan 25° = PS/QS, so QS = 5 sin 65°/tan 25° = 5 cot 25° sin 65°.