Question 10
Acids, Bases and SaltsDetermine the PH of a 2.50×10−5M solution of potassium hydroxide.
- A.3.6
- B.9.4
- C.5.0
- D.12.0
Show the answer and explanation
Answer: B (9.4)
Explanation
KOH ionises fully, so [OH−] = 2.5 × 10−5 and pOH = −log(2.5 × 10−5) ≈ 4.6. pH = 14 − 4.6 = 9.4.