Question 23
Redox ReactionsThe oxidation number of boron in NaBH4 is
- A.−3
- B.−1
- C.+1
- D.+3
Show the answer and explanation
Answer: D (+3)
Explanation
Na is +1 and each H (a hydride) is −1: 1 + x − 4 = 0, so x = +3.
The oxidation number of boron in NaBH4 is
Answer: D (+3)
Na is +1 and each H (a hydride) is −1: 1 + x − 4 = 0, so x = +3.