Question 21
Mole Concept and StoichiometryDuring a titration experiment, 0.05 moles of carbon(IV) oxide is liberated. What is the volume of gas liberated? [Molar volume of a gas at s.t.p. = 22.4 dm3]
- A.22.40 dm3
- B.11.20 dm3
- C.2.24 dm3
- D.1.12 dm3
Show the answer and explanation
Answer: D (1.12 dm3)
Explanation
Volume = 0.05 × 22.4 = 1.12 dm3.