passwella.
Menu

JAMB Chemistry 1979 Question 17

Question 17

Alkanoic Acids and Esters

The structural formula of ethanoic acid is

  1. A.H–C(=O)–OH
  2. B.CH3–C(=O)–H
  3. C.CH3–CH2–C(=O)–H
  4. D.CH3–CH2–C(=O)–OH
  5. E.CH3–C(=O)–OH
Show the answer and explanation

Answer: E (CH3–C(=O)–OH)

Explanation

Ethanoic acid has two carbons and the –COOH group: CH3COOH. A is methanoic acid, B and C are aldehydes and D is propanoic acid.