Question 15
Mole Concept and StoichiometryHow many grams of HBr would exactly be required to react with 2 g of propyne? (C = 12, H = 1, Br = 80)
- A.4.1 g
- B.6.1 g
- C.8.1 g
- D.10.1g
- E.16.2g
Show the answer and explanation
Answer: C (8.1 g)
Explanation
Propyne C3H4 (40 g/mol) adds 2 HBr across its triple bond. 2 g = 0.05 mol, which needs 0.10 mol HBr = 0.10 × 81 = 8.1 g.